读取zip包中的文件

private List<String> readFile(String zipFilePath,String fileName){File file = new File(zipFilePath);List<String> list;System.out.println(file.getName());//20250709-5427327003468403533.ziptry {ZipFile zipFile = new ZipFile(file);InputStream stream = ZipUtil.getStream(zipFile, new ZipEntry(fileName));list = new ArrayList<>();if (stream != null) {//String content = IoUtil.read(stream, "UTF-8");
                IoUtil.readLines(stream, CharEncoding.UTF_8, list);}IoUtil.close(stream);return list;} catch (Exception e) {e.printStackTrace();}return null;}

读取zip中的某一个文件，将行内容放到list里面