【BISHI15】小红的夹吃棋

求解代码

publicstaticvoidmain(String[]args)throwsIOException{BufferedReaderbr=newBufferedReader(newInputStreamReader(System.in));StringTokenizerin=newStringTokenizer(br.readLine());PrintWriterout=newPrintWriter(newOutputStreamWriter(System.out));intt=Integer.parseInt(in.nextToken());for(inti=0;i<t;i++){char[][]board=newchar[3][3];for(intj=0;j<3;j++){Strings=br.readLine().trim();board[j]=s.toCharArray();}booleanredEat=hasEat(board,'*');booleanpurpleEat=hasEat(board,'o');if(redEat&&!purpleEat){out.println("yukari");}elseif(!redEat&&purpleEat){out.println("kou");}else{out.println("draw");}}out.flush();out.close();br.close();}privatestaticbooleanhasEat(char[][]board,charpiece){charopponent=(piece=='*')?'o':'*';//遍历 3 行（行索引 0-2），// 仅检查 “该行中间列（索引 1）是己方棋子，// 左右列（索引 0、2）全是对方棋子”for(introw=0;row<3;row++){if(board[row][1]==piece&&board[row][0]==opponent&&board[row][2]==opponent){returntrue;}}//遍历 3 列（列索引 0-2），// 仅检查 “该列中间行（索引 1）是己方棋子，// 上下行（索引 0、2）全是对方棋子”for(intcol=0;col<3;col++){if(board[1][col]==piece&&board[0][col]==opponent&&board[2][col]==opponent){returntrue;}}returnfalse;}

小贴士

逐行读取 3 行字符串时需要用br.readLine().trim()，可以避免StringTokenizer的分割符问题，其实这题用in.nextToken()还过不了。