leetcode 1630. 等差子数组-Arithmetic Subarrays

Problem: 1630. 等差子数组-Arithmetic Subarrays

单独拷贝子数组到一个新的数组内，然后排序的，若满足前后的差值相同，则是等差数列，否则不是的

Code

class Solution { public: vector<bool> checkArithmeticSubarrays(vector<int>& nums, vector<int>& l, vector<int>& r) { int n = l.size(), ll, rr, d; bool arithmetic; vector<bool> ret; for(int i = 0; i < n; i++) { ll = l[i]; rr = r[i]; vector<int> tr(nums.begin() + ll, nums.begin() + rr + 1); sort(tr.begin(), tr.end()); arithmetic = true; d = tr[1] - tr[0]; for(int i = 2; i < tr.size(); i++) { if(tr[i] - tr[i-1] != d) { arithmetic = false; break; } } ret.push_back(arithmetic); } return ret; } };